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Class 12 · Chapter 10 · Vectors and Three-Dimensional Geometry unit (14 of 80 marks)

Vector Algebra Class 12: notes and important questions

Revision notes, 39 board-style questions with the step marks shown, and a four-step route from the basics to 95+, each step ending in a short checkpoint.

  • 39 questions
  • 12 multiple choice, 3 assertion–reason, 9 very short answer, 8 short answer, 4 long answer, 3 case study
  • About 7 hours to master

Unit IV Vectors and Three-Dimensional Geometry: 14 marks of the 80-mark paper (shared with Chapter 11) — CBSE Curriculum 2025-26 Mathematics (041), https://cbseacademic.nic.in/web_material/CurriculumMain26/SrSec/Maths_SrSec_2025-26.pdf.

Revision notes

Vector Algebra — revision notes

1. Basics

  • \(\vec{r} = x\hat{i} + y\hat{j} + z\hat{k}\): magnitude \(|\vec{r}| = \sqrt{x^2 + y^2 + z^2}\), unit vector \(\hat{r} = \dfrac{\vec{r}}{|\vec{r}|}\).
  • \(\overrightarrow{AB} = \vec{b} - \vec{a}\) (position vector of head minus tail).
  • Direction cosines \(l = \dfrac{x}{r}, m = \dfrac{y}{r}, n = \dfrac{z}{r}\) with \(l^2 + m^2 + n^2 = 1\); direction ratios are any multiple \((x, y, z)\).
  • Collinear (parallel) vectors: \(\vec{b} = \lambda\vec{a}\), i.e. components in the same ratio.

2. Section formula

Point dividing \(AB\) internally in \(m : n\): \(\dfrac{n\vec{a} + m\vec{b}}{m + n}\); externally: \(\dfrac{m\vec{b} - n\vec{a}}{m - n}\); midpoint \(\dfrac{\vec{a} + \vec{b}}{2}\).

3. Scalar (dot) product

  • \(\vec{a}\cdot\vec{b} = |\vec{a}||\vec{b}|\cos\theta = a_1b_1 + a_2b_2 + a_3b_3\); \(\theta \in [0, \pi]\).
  • \(\vec{a} \perp \vec{b} \iff \vec{a}\cdot\vec{b} = 0\); \(\vec{a}\cdot\vec{a} = |\vec{a}|^2\).
  • Projection of \(\vec{a}\) on \(\vec{b}\): \(\dfrac{\vec{a}\cdot\vec{b}}{|\vec{b}|}\); projection vector \(\left(\dfrac{\vec{a}\cdot\vec{b}}{|\vec{b}|^2}\right)\vec{b}\).
  • \(|\vec{a} \pm \vec{b}|^2 = |\vec{a}|^2 + |\vec{b}|^2 \pm 2\vec{a}\cdot\vec{b}\) — the key tool for magnitude problems.

4. Vector (cross) product

  • \(\vec{a}\times\vec{b} = |\vec{a}||\vec{b}|\sin\theta\,\hat{n}\) (right-hand rule) \(= \begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\a_1&a_2&a_3\\b_1&b_2&b_3\end{vmatrix}\).
  • \(\vec{b}\times\vec{a} = -\vec{a}\times\vec{b}\); \(\vec{a}\times\vec{a} = \vec{0}\); \(\vec{a}\parallel\vec{b} \iff \vec{a}\times\vec{b} = \vec{0}\).
  • Area of parallelogram \(= |\vec{a}\times\vec{b}|\) (adjacent sides) \(= \tfrac12|\vec{d}_1\times\vec{d}_2|\) (diagonals); area of triangle \(ABC = \tfrac12|\overrightarrow{AB}\times\overrightarrow{AC}|\).
  • Unit vector perpendicular to \(\vec{a}\) and \(\vec{b}\): \(\pm\dfrac{\vec{a}\times\vec{b}}{|\vec{a}\times\vec{b}|}\). Also \(|\vec{a}\times\vec{b}|^2 + (\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2\).

Worked example 1

\(|\vec{a}| = 2\), \(|\vec{b}| = 3\), \(\vec{a}\cdot\vec{b} = 3\): \(|\vec{a} - \vec{b}|^2 = 4 + 9 - 6 = 7\), so \(|\vec{a} - \vec{b}| = \sqrt7\); \(\cos\theta = \tfrac12\), \(\theta = \tfrac\pi3\).

Worked example 2

Area of the triangle with vertices \((0, 0, 0)\), \((1, 2, 0)\), \((0, 1, 3)\): \((\hat{i} + 2\hat{j})\times(\hat{j} + 3\hat{k}) = 6\hat{i} - 3\hat{j} + \hat{k}\), area \(= \tfrac12\sqrt{46}\).

Worked example 3

Point dividing \(A(2, 1, 3)\), \(B(5, 7, 0)\) in \(1 : 2\): \(\dfrac{2(2, 1, 3) + (5, 7, 0)}{3} = (3, 3, 2)\).

Common errors

  • Middle term of the cross-product determinant: it is \(-\hat{j}(a_1b_3 - a_3b_1)\).
  • Using \(\tfrac{m\vec{a} + n\vec{b}}{m + n}\) (weights swapped) in the section formula.
  • Giving only one sign for a unit perpendicular vector, or the wrong one when a condition (acute/obtuse with an axis) is given.
  • Confusing the scalar projection (a number) with the projection vector.
  • Writing \(|\vec{a} + \vec{b}| = |\vec{a}| + |\vec{b}|\).

Board-exam tips

  • For “find the angle” questions, write \(\cos\theta = \dots\) and the final \(\theta = \cos^{-1}(\cdot)\) if it is not standard.
  • Scalar triple product and coplanarity are not in the current syllabus.

Topics in this chapter: Vectors: magnitude, direction and types · Direction cosines and direction ratios · Addition, scalar multiple and section formula · Scalar (dot) product and projection · Vector (cross) product and area.

Route to 95: four steps

Work through the steps in order. Take each checkpoint closed book, about 1.5 minutes per mark; pass at 80% to move on. Two misses in a row means going back one step.

Step 1

Secure the basics

Find magnitudes, unit vectors, direction cosines, section-formula points and simple dot/cross products.

Read first: 1. Basics; 2. Section formula 6 practice questions · checkpoint: 3 questions, 5 marks, pass 80%
Practise step 1
Step 2

Board standard

Use dot and cross products for angles, projections, perpendicularity, collinearity and areas at 2- and 3-mark level.

Read first: 3. Scalar (dot) product; 4. Vector (cross) product 23 practice questions · checkpoint: 4 questions, 8 marks, pass 75%
Practise step 2
Step 3

Full marks on long answers

Write complete multi-step vector solutions (triangle and parallelogram problems, case studies with forces or displacements).

Read first: Worked examples 1-3; 4. Vector (cross) product (areas) 4 practice questions · checkpoint: 3 questions, 14 marks, pass 70%
Practise step 3
Step 4

95+ stretch (HOTS)

Work with vectors given only by magnitudes and angles, minimisation and perpendicular-component arguments.

Read first: 3. Scalar (dot) product (|a ± b|² identity) 6 practice questions · checkpoint: 3 questions, 13 marks, pass 60%
Practise step 4

Practice questions

Original questions in the board's styles. Multiple-choice answers are checked as you go; for written answers, compare your working with the step mark scheme and record your marks. 3 of the 39 are competency-based (case studies and questions set in a real-life situation): the "Competency-based" button shows just those.

Q1·1 mark·Multiple choiceVectors: magnitude, direction and types

A vector of magnitude \(14\) in the direction opposite to \(2\hat{i} - 3\hat{j} + 6\hat{k}\) is

  1. (a)\(4\hat{i} - 6\hat{j} + 12\hat{k}\)
  2. (b)\(-4\hat{i} + 6\hat{j} - 12\hat{k}\)
  3. (c)\(-28\hat{i} + 42\hat{j} - 84\hat{k}\)
  4. (d)\(-2\hat{i} + 3\hat{j} - 6\hat{k}\)
Q2·1 mark·Multiple choiceAddition, scalar multiple and section formula

The position vectors of \(A\) and \(B\) are \(\hat{i} + 2\hat{j} - \hat{k}\) and \(6\hat{i} - 3\hat{j} + 4\hat{k}\). The position vector of the point dividing \(AB\) internally in the ratio \(2 : 3\) is

  1. (a)\(\tfrac72\hat{i} - \tfrac12\hat{j} + \tfrac32\hat{k}\)
  2. (b)\(4\hat{i} - \hat{j} + 2\hat{k}\)
  3. (c)\(3\hat{i} + \hat{k}\)
  4. (d)\(3\hat{i} + 2\hat{k}\)
Q3·1 mark·Multiple choiceVector (cross) product and area

\((2\hat{i} - \hat{j}) \times (\hat{i} + 3\hat{k})\) equals

  1. (a)\(-3\hat{i} + 6\hat{j} + \hat{k}\)
  2. (b)\(3\hat{i} + 6\hat{j} - \hat{k}\)
  3. (c)\(-3\hat{i} - 6\hat{j} + \hat{k}\)
  4. (d)\(2\hat{i} - 3\hat{k}\)

Where marks are lost in Vector Algebra

  • Sign error in the ĵ-term of a cross product. Fix: write −ĵ(a₁b₃ − a₃b₁) explicitly, then check that the answer is perpendicular to both vectors (dot = 0).
  • Section formula with weights swapped. Fix: the point dividing AB in m : n is (n·a + m·b)/(m + n) — the weight of b is the part nearer A.
  • Only one of ± for a unit perpendicular vector. Fix: give ±, then apply any stated condition (e.g. acute angle with the z-axis) to choose.
  • Area of triangle given as |AB × AC| (forgetting ½), or parallelogram from diagonals without ½. Fix: write the formula before substituting.
  • Treating magnitudes as additive: |a + b| = |a| + |b|. Fix: square and use |a + b|² = |a|² + |b|² + 2a·b.
  • Stopping at cos θ = 4/9 without stating θ. Fix: finish with θ = cos⁻¹(4/9).

Examiner Insights: common mistakes in CBSE Class 12 Maths, with fixes (our analysis of public sources) →

Vector Algebra in our sample papers

Once step 3 is passed, test the chapter inside a full timed paper on the 2026-27 pattern (original papers by us, not official CBSE papers).