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Class 10 · Chapter 14 · Statistics and Probability unit (11 of 80 marks)

Probability Class 10: notes and important questions

Revision notes, 37 board-style questions with the step marks shown, and a four-step route from the basics to 95+, each step ending in a short checkpoint.

  • 37 questions
  • 10 multiple choice, 3 assertion–reason, 8 very short answer, 8 short answer, 5 long answer, 3 case study
  • About 8 hours to master

Statistics & Probability unit: 11 of 80 theory marks (Statistics and Probability).

Revision notes

Theoretical (classical) probability

If an experiment has \(n\) equally likely outcomes, and \(m\) of them are favourable to event \(E\), then

\(P(E)=\dfrac{\text{number of outcomes favourable to }E}{\text{total number of possible outcomes}}=\dfrac mn\).

  • \(0\le P(E)\le1\). A sure event has probability 1 and an impossible event has probability 0.
  • Complementary events: \(P(E)+P(\bar E)=1\), where \(\bar E\) is "not \(E\)".
  • An event with a single outcome is an elementary event. The probabilities of all elementary events of an experiment add to 1.

Standard sample spaces

  • One coin: {H, T}. Two coins: {HH, HT, TH, TT}. Three coins: 8 outcomes.
  • One die: {1, 2, 3, 4, 5, 6}. Two dice: 36 ordered pairs \((a,b)\). Sum 7 occurs 6 times, the most of any sum.
  • A pack of 52 cards: 4 suits (spades ♠ and clubs ♣ black; hearts ♥ and diamonds ♦ red), 13 cards each. Face cards are king, queen and jack: 12 in all. There are 4 aces.

Worked example 1

Two dice are thrown. Find the probability that the sum is 9.   Favourable: (3,6), (4,5), (5,4), (6,3), so \(P=\frac{4}{36}=\frac19\).

Worked example 2

A card is drawn from a well-shuffled pack. Find \(P(\text{a black face card})\).   There are 6 black face cards, so \(P=\frac{6}{52}=\frac{3}{26}\).

Worked example 3

A bag has 6 red balls and some blue balls. The probability of drawing a blue ball is \(\frac35\). How many blue balls are there?

\(\frac{b}{6+b}=\frac35\Rightarrow5b=18+3b\Rightarrow b=9\).

Common errors

  • Treating "HT" and "TH" as one outcome, or listing (2,3) but not (3,2) for two dice.
  • Forgetting that 1 is neither prime nor composite.
  • Counting 16 face cards (the aces are not face cards).
  • Not reducing the fraction, or giving a probability greater than 1.

Board-exam tips

  • Write the total number of outcomes and list the favourable outcomes explicitly. Each step earns a mark.
  • Use \(P(\text{not }E)=1-P(E)\) when "not", "at least one" or "neither" is asked.
  • Only the classical (theoretical) approach is examined. The optional Exercise 14.2 has been removed from the rationalised book.

Topics in this chapter: Basic properties of probability · Probability with dice · Probability with coins · Probability with playing cards · Simple events · Complementary events.

Route to 95: four steps

Work through the steps in order. Take each checkpoint closed book, about 1.5 minutes per mark; pass at 80% to move on. Two misses in a row means going back one step.

Step 1

Secure the basics

You know that probabilities lie between 0 and 1, can use P(not E) = 1 − P(E), and can find simple probabilities.

Read first: Theoretical (classical) probability 12 practice questions · checkpoint: 4 questions, 7 marks, pass 80%
Practise step 1
Step 2

Board standard

You can list outcomes for coins, dice and cards correctly and solve the standard board questions on each.

Read first: Standard sample spaces; Worked examples 1-2 12 practice questions · checkpoint: 4 questions, 10 marks, pass 80%
Practise step 2
Step 3

Full marks on long answers

You can write complete long answers and case studies, listing favourable outcomes and giving answers in lowest terms.

Read first: Standard sample spaces; Worked example 3; Board-exam tips 7 practice questions · checkpoint: 3 questions, 14 marks, pass 80%
Practise step 3
Step 4

95+ stretch (HOTS)

You can handle two-dice products and sums, modified card packs and 'find the number of balls' problems.

Read first: Standard sample spaces; Common errors 6 practice questions · checkpoint: 3 questions, 11 marks, pass 80%
Practise step 4

Practice questions

Original questions in the board's styles. Multiple-choice answers are checked as you go; for written answers, compare your working with the step mark scheme and record your marks. 5 of the 37 are competency-based (case studies and questions set in a real-life situation): the "Competency-based" button shows just those.

Q1·1 mark·Multiple choiceBasic properties of probability

A die is thrown once. Which of the following is an impossible event?

  1. (a)getting 6
  2. (b)getting 0
  3. (c)getting an odd number
  4. (d)getting a number less than 7
Q2·1 mark·Multiple choiceBasic properties of probability

The probability of a sure event is

  1. (a)0
  2. (b)1
  3. (c)\(\frac12\)
  4. (d)more than 1
Q3·1 mark·Assertion–reasonBasic properties of probability

In the following question, a statement of Assertion (A) is followed by a statement of Reason (R). Choose the correct option.

Assertion (A): The probability of getting a number greater than 6 in a single throw of a die is 0.

Reason (R): The probability of an impossible event is 0.

  1. (a)Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A).
  2. (b)Both Assertion (A) and Reason (R) are true but Reason (R) is not the correct explanation of Assertion (A).
  3. (c)Assertion (A) is true but Reason (R) is false.
  4. (d)Assertion (A) is false but Reason (R) is true.

Where marks are lost in Probability

  • Treating HT and TH (or (2, 3) and (3, 2)) as one outcome. Fix: write the full sample space (4 for two coins, 36 for two dice) before counting.
  • Counting 16 face cards by including aces. Fix: face cards are J, Q, K only: 12 in a pack; aces are not face cards.
  • Forgetting that 1 is neither prime nor composite. Fix: list the primes explicitly when counting.
  • Not reducing the fraction, or giving a probability above 1. Fix: simplify every answer and check 0 ≤ P ≤ 1.
  • Not writing the total number of outcomes and the favourable list. Fix: write 'Total outcomes = 36, favourable = {(4, 5), (5, 4), …} = 4'; each part is marked.
  • Modified packs (cards removed): using 52 as the total. Fix: recount the total and each category after removal, on paper.

Probability in our sample papers

Once step 3 is passed, test the chapter inside a full timed paper on the 2026-27 pattern (original papers by us, not official CBSE papers).