Skip to main content
Class 10 · Chapter 2 · Algebra unit (20 of 80 marks)

Polynomials Class 10: notes and important questions

Revision notes, 10 free important questions with step-marked answers, and a four-step route from the basics to 95+ through 41 board-style questions.

Practise this chapterJoin freeFree account, no card: +5 practice questions on every chapter, with instant feedback.

  • 41 questions
  • 13 multiple choice, 3 assertion–reason, 9 very short answer, 8 short answer, 5 long answer, 3 case study
  • About 8 hours to master

Algebra unit: 20 of 80 theory marks (Polynomials, Pair of Linear Equations, Quadratic Equations, Arithmetic Progressions).

NCERT textbook: Chapter 2 on ncert.nic.in (PDF)

Try it first

1 of 5

  1. Question 1 of 5
  2. Question 2 of 5
  3. Question 3 of 5
  4. Question 4 of 5
  5. Question 5 of 5

Start with one question on polynomials. Stuck? Take a hint. No sign-in needed.

If one zero of 5x2+13x+k is the reciprocal of the other, then k equals

Choose your answer · keys 1–4

Revision notes

Polynomials — revision notes

1. Basics

  • Degree = highest power of the variable. Linear (degree 1), quadratic (degree 2), cubic (degree 3).
  • A zero of p(x) is a number k with p(k)=0. A polynomial of degree n has at most n zeroes.

2. Geometrical meaning of zeroes

  • The zeroes of p(x) are the x-coordinates of the points where the graph of y=p(x) meets the x-axis.
  • y=ax+b is a straight line: exactly one zero, −ba.
  • y=ax2+bx+c is a parabola, opening upward if a>0 and downward if a<0. It can meet the x-axis at 2 points, touch it at 1 point, or miss it (0 zeroes).

3. Zeroes and coefficients (quadratic ax2+bx+c)

α+β=−ba,αβ=ca

Useful identities: α2+β2=(α+β)2−2αβ; (α−β)2=(α+β)2−4αβ; α3+β3=(α+β)3−3αβ(α+β); 1α+1β=α+βαβ.

4. Forming a quadratic polynomial

With sum S and product P of zeroes: k[x2−Sx+P], k≠0. Multiply by a suitable k to clear fractions.

Worked example 1

Zeroes of 3x2+5x−2: split −6=6×(−1): 3x2+6x−x−2=(3x−1)(x+2). Zeroes 13,−2. Check: sum −53=−ba, product −23=ca.

Worked example 2

Polynomial with zeroes 3±2: S=6, P=9−2=7, so x2−6x+7.

Worked example 3

If α,β are zeroes of x2−4x+1, find α2+β2: 16−2=14.

Common errors

  • Sign slip: the sum of zeroes is −b/a, not b/a.
  • Writing x2+Sx+P instead of x2−Sx+P.
  • Stating that a quadratic “has exactly 2 zeroes” — it may have 0, 1 or 2 real zeroes.
  • When verifying the relationship, forgetting to compare with −b/a and c/a explicitly.

Board-exam tips

  • “Find zeroes and verify” questions are 2–3 marks: factorise by splitting the middle term, then show both checks.
  • For expressions in α,β, never solve for the zeroes unless asked — use the identities.
  • Graph-reading MCQs: count intersections with the x-axis only (not the y-axis).

Topics in this chapter: Geometrical meaning of the zeroes · Zeroes of a polynomial · Relationship between zeroes and coefficients · Forming a quadratic polynomial.

Formulas for this chapter: Chapter 2 on the Class 10 formula sheet (free PDF and A3 poster).

Polynomials Class 10: important questions

10 original questions in the board paper's question types, from 1-mark MCQs to a case study, each with a step-marked worked answer. Try each one first. 5 worked answers open here; the other 5 open with a free account (no card).

Download these questions (PDF) 10 questions, 5 worked answers · 5 pages · 178 KB

Section A style · Multiple choice and assertion–reason (1 mark each)

Q1·1 mark·Multiple choiceRelationship between zeroes and coefficients

3 is one zero of 3x2−10x+k. The other zero is

Show worked answer

27−30+k=0⇒k=3; product of zeroes =k3=1, so the other zero is 13 A1
Correct option: (a) 13

Q2·1 mark·Multiple choiceRelationship between zeroes and coefficients

If α and β are the zeroes of x2−4x+1, then α2+β2 equals

Q3·1 mark·Assertion–reasonZeroes of a polynomial

In the following question, a statement of Assertion (A) is followed by a statement of Reason (R). Choose the correct option.

Assertion (A): The polynomial x2−6x+9 has two equal zeroes.

Reason (R): Every quadratic polynomial has two distinct real zeroes.

Section B style · Short answer (2 marks each)

Q4·2 marks·Short answerRelationship between zeroes and coefficients

Find the zeroes of 3x2−27. Check that their sum is −ba and their product is ca.

Show worked answer
Answer: 3 and −3

3x2−27=3(x−3)(x+3), so the zeroes are 3 and −3 M1
Sum =0=−03; product =−9=−273 A1

Q5·2 marks·Short answerForming a quadratic polynomial

Find a quadratic polynomial with integer coefficients whose zeroes are −23 and 12.

Section C style · Short answer (3 marks each)

Q6·3 marks·Short answerRelationship between zeroes and coefficients

α and β are the zeroes of 2x2−3x−6. Without finding the zeroes, find 1α+1β and α2β+αβ2.

Show worked answer
Answer: −12 and −92

α+β=32 and αβ=−3 A1
1α+1β=α+βαβ=3/2−3=−12 A1
α2β+αβ2=αβ(α+β)=−3×32=−92 A1

Q7·3 marks·Short answerRelationship between zeroes and coefficients

Factorise 6x2−13x+6 to find its zeroes. Then check that their sum and product agree with the coefficients.

Section D style · Long answer (5 marks each)

Q8·5 marks·Long answerForming a quadratic polynomial

The zeroes α and β of x2−9x+k satisfy α−β=3. Find k. Hence find a quadratic polynomial whose zeroes are αβ and βα.

Show worked answer
Answer: k=18; 2x2−5x+2

α+β=9 and αβ=k M1
With α−β=3: α=6, β=3 A1
k=αβ=18 A1
αβ=2, βα=12: sum =52, product =1 M1
Polynomial: x2−52x+1, or 2x2−5x+2 A1

Q9·5 marks·Long answerRelationship between zeroes and coefficients

α and β are the zeroes of p(x)=2x2+5x+k, and α2+β2+αβ=214. Find k and the zeroes of p(x).

Section E style · Case study (4 marks)

Q10·4 marks·Case studyGeometrical meaning of the zeroes

Flower bed. The area of a rectangular flower bed is p(x)=x2+x−12 square metres, where its length and breadth (in metres) are the two linear factors of p(x).

  1. Factorise p(x) to write the length and the breadth in terms of x. [1 mark]

  2. Find the zeroes of p(x). [1 mark]

  3. The length of the bed is 9 m. Find x and the area of the bed. [2 marks]

Show worked answer
  1. x2+4x−3x−12=(x+4)(x−3): length (x+4) m, breadth (x−3) m A1

  2. (x+4)(x−3)=0⇒x=−4 or x=3 A1

  3. x+4=9⇒x=5; breadth =5−3=2 m M1
    Area =9×2=18 m2 (check: p(5)=25+5−12=18) A1

Next: practise by Route to 95 step · the revision notes · free MCQs and case studies · all Class 10 assertion–reason questions · the Class 10 syllabus checklist.

Route to 95: four steps

Work through the steps in order. Take each checkpoint closed book, about 1.5 minutes per mark; pass at 80% to move on. Two misses in a row means going back one step.

Step 1

Secure the basics

You can find the zeroes of a quadratic by splitting the middle term and read the number of zeroes from a graph.

Read first: 1. Basics; 2. Geometrical meaning of zeroes 9 practice questions · checkpoint: 4 questions, 8 marks, pass 80%
Practise step 1
Step 2

Board standard

You can use sum = −b/a and product = c/a confidently, verify the relationship, and build a quadratic from given zeroes.

Read first: 3. Zeroes and coefficients (quadratic ax² + bx + c); 4. Forming a quadratic polynomial; Worked examples 1-2 16 practice questions · checkpoint: 4 questions, 9 marks, pass 80%
Practise step 2
Step 3

Full marks on long answers

You can write full-marks long answers and case studies, including completing a table, plotting the graph and reading off the zeroes.

Read first: 2. Geometrical meaning of zeroes; 3. Zeroes and coefficients; Board-exam tips 6 practice questions · checkpoint: 3 questions, 14 marks, pass 80%
Practise step 3
Step 4

95+ stretch (HOTS)

You can handle expressions like α² + β² or α/β + β/α without solving, and build new polynomials whose zeroes are changed versions of old ones.

Read first: 3. Zeroes and coefficients; 4. Forming a quadratic polynomial; Worked example 3 8 practice questions · checkpoint: 3 questions, 9 marks, pass 80%
Practise step 4

Practice questions

Original questions in the board's styles. Multiple-choice answers are checked as you go; for written answers, compare your working with the step mark scheme and record your marks. 3 of the 41 are competency-based (case studies and questions set in a real-life situation): the "Competency-based" button shows just those.

Q1·1 mark·Multiple choiceZeroes of a polynomial

The zeroes of x2−2x−15 are

  1. (a)3,−5
  2. (b)−3,−5
  3. (c)3,5
  4. (d)−3,5
Q2·1 mark·Multiple choiceZeroes of a polynomial

If 2 is a zero of 3x2−8x+k, then the value of k is

  1. (a)4
  2. (b)−4
  3. (c)28
  4. (d)−28
Q3·1 mark·Multiple choiceZeroes of a polynomial

Which of the following is a quadratic polynomial?

  1. (a)x2+1x
  2. (b)x+4
  3. (c)3−2x+2x2
  4. (d)x3−x
Worked solution·2 marks·Very short answerRelationship between zeroes and coefficients

Find the zeroes of 6x2−7x−3 and verify the relationship between the zeroes and the coefficients.

Full worked solution Free, no sign-in

6x2−9x+2x−3=(2x−3)(3x+1); zeroes 32, −13 A1
Sum =32−13=76=−−76; product =−12=−36 ✓ A1

Every question here has a full worked solution. See them all →

Stretch yourself: original algebra problems at Intermediate level (ages 13 to 16), with hints and full solutions: Problem I121 · Problem I24 · Problem I106 · Problem I113. All 29 →

Knowledge organiser: Polynomials on one page (key facts, formulas and mistakes to avoid; printable PDF)

Where marks are lost in Polynomials

  • Sign slip in the sum of zeroes: writing b/a instead of −b/a. Fix: write 'α + β = −b/a = …' with the formula before substituting.
  • Forming the polynomial as x² + Sx + P. Fix: memorise k[x² − (sum)x + (product)] and include 'k' when asked for 'a' quadratic polynomial.
  • In 'find the zeroes and verify', stopping after the zeroes. Fix: show both checks, sum vs −b/a and product vs c/a, each on its own line; they carry separate marks.
  • Solving for α and β when the question only needs α² + β² or 1/α + 1/β. Fix: use identities (α² + β² = (α + β)² − 2αβ), which is shorter and is what the scheme rewards.
  • Graph MCQs: counting where the curve meets the y-axis, or counting a touching point twice. Fix: count only distinct points on the x-axis.
  • Surd coefficients (e.g. 2√3x² − 5x + √3): splitting the middle term with the wrong product. Fix: multiply a × c first (here 6) and look for factors of that number.

Exam strategy: how answers are step-marked · competency-based questions

Polynomials in our sample papers

Once step 3 is passed, test the chapter inside a full timed paper on the 2026-27 pattern (original papers by us, not official CBSE papers).

Want it against the clock? Take a timed 30-mark chapter test on Polynomials, new questions each time, or climb the Difficulty ladder, levels 1 to 10, three questions a level (CBSE Pro or the free trial).

Polynomials: common questions

What is in CBSE Class 10 Maths Chapter 2, Polynomials?

The topics are: Geometrical meaning of the zeroes, Zeroes of a polynomial, Relationship between zeroes and coefficients, Forming a quadratic polynomial. This page has revision notes for each, and 41 board-style practice questions with step-marked solutions.

How many marks is Polynomials worth?

It is in the Algebra unit, which carries 20 of the 80 theory marks. CBSE gives marks by unit, not by chapter.

Where do students lose marks in Polynomials?

Sign slip in the sum of zeroes: writing b/a instead of −b/a. Fix: write 'α + β = −b/a = …' with the formula before substituting. Forming the polynomial as x² + Sx + P. Fix: memorise k[x² − (sum)x + (product)] and include 'k' when asked for 'a' quadratic polynomial.

Are the Polynomials important questions free?

Yes. The 10 important questions on this page are free to try, from 1-mark MCQs to a case study. 5 worked answers are open on the page; the others open with a free account (no card).

Are these NCERT questions?

No. Every practice question here is original, written in the board's question styles with step marks. For the textbook itself, use the NCERT link on this page.

Work through the Route to 95 with your progress saved

Save your answers and track your progressA free account remembers the questions you have done and brings you back to this page.

Join free

Already have an account? Sign in