Polynomials Class 10: MCQ and case study questions
15 multiple-choice questions and 2 case-based questions on the current (rationalised) syllabus, in the style of the board paper's Sections A and E. Try each one first; the answer, a one-line reason and a worked solution open on a tap.
15 MCQs (1 mark each)
2 case studies (4 marks each)
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Multiple-choice questions
Choose one option. Section A of the board paper has 18 MCQs of 1 mark each, spread over all chapters.
Q1
·1 mark·Multiple choiceZeroes of a polynomial
The zeroes of the polynomial \(x^2 - 9x + 14\) are
If \(-4\) is a zero of \(x^2 + kx - 20\), then \(k\) equals
(a)\(1\)
(b)\(4\)
(c)\(9\)
(d)\(-1\)
Show answer
Answer: (d) \(-1\)
Why: Substitute x = −4 and set the value to 0.
\((-4)^2 + k(-4) - 20 = 0 \Rightarrow 16 - 4k - 20 = 0 \Rightarrow k = -1\). (The other zero is \(5\).)
Q5
·1 mark·Multiple choiceGeometrical meaning of zeroes
The graph of a quadratic polynomial \(y = p(x)\) touches the \(x\)-axis at exactly one point and does not cross it. The number of distinct zeroes of \(p(x)\) is
(a)\(0\)
(b)\(1\)
(c)\(2\)
(d)\(3\)
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Answer: (b) \(1\)
Why: The zeroes are the x-coordinates of the points where the graph meets the x-axis.
Each point where the graph meets the \(x\)-axis gives one zero. One point of contact gives exactly one zero (e.g. \(y = (x-2)^2\) has only the zero \(2\)).
Q6
·1 mark·Multiple choiceRelationship between zeroes and coefficients
If \(\alpha\) and \(\beta\) are the zeroes of \(x^2 - 6x + 5\), then \(\alpha^2\beta + \alpha\beta^2\) equals
·1 mark·Multiple choiceRelationship between zeroes and coefficients
The zeroes of \(x^2 - 12x + k\) are in the ratio \(1 : 5\). The value of \(k\) is
(a)\(20\)
(b)\(27\)
(c)\(11\)
(d)\(36\)
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Answer: (a) \(20\)
Why: Let the zeroes be a and 5a: 6a = 12 gives a = 2, so k = 2 × 10.
Zeroes \(a\) and \(5a\): \(a + 5a = 12 \Rightarrow a = 2\). Zeroes \(2\) and \(10\); \(k = \) product \(= 20\).
Q8
·1 mark·Multiple choiceRelationship between zeroes and coefficients
If one zero of \(5x^2 + 13x + k\) is the reciprocal of the other, then \(k\) equals
(a)\(-5\)
(b)\(13\)
(c)\(\dfrac15\)
(d)\(5\)
Show answer
Answer: (d) \(5\)
Why: Zeroes α and 1/α have product 1, and product = k/5.
Product of zeroes \(= \alpha \cdot \dfrac1\alpha = 1 = \dfrac{k}{5}\), so \(k = 5\). (Then \(5x^2 + 13x + 5\) has real zeroes since \(169 - 100 \gt 0\).)
Q9
·1 mark·Multiple choiceZeroes of a polynomial
The zeroes of \(x^2 - 3\) are
(a)\(3\) and \(-3\)
(b)\(9\) and \(-9\)
(c)\(\sqrt3\) and \(-\sqrt3\)
(d)\(3\) and \(0\)
Show answer
Answer: (c) \(\sqrt3\) and \(-\sqrt3\)
Why: x² = 3 gives x = ±√3.
\(x^2 - 3 = (x - \sqrt3)(x + \sqrt3)\), so the zeroes are \(\sqrt3\) and \(-\sqrt3\).
Q10
·1 mark·Multiple choiceRelationship between zeroes and coefficients
For the quadratic polynomial \(ax^2 + bx + c\) (\(a \ne 0\)), if \(c = 0\) then
(a)both zeroes are \(0\)
(b)one zero is \(0\)
(c)the zeroes are equal
(d)the zeroes are reciprocals of each other
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Answer: (b) one zero is \(0\)
Why: c = 0 makes the product of zeroes c/a = 0, so one zero is 0.
With \(c = 0\): \(ax^2 + bx = x(ax + b)\), whose zeroes are \(0\) and \(-\dfrac{b}{a}\). So one zero is \(0\) (both only if also \(b = 0\)).
Q11
·1 mark·Multiple choiceGeometrical meaning of zeroes
For some \(b \gt 0\), the graph of \(y = x^2 + bx + 9\) touches the \(x\)-axis at exactly one point. That point is
(a)\((-3, 0)\)
(b)\((3, 0)\)
(c)\((0, 9)\)
(d)\((-6, 0)\)
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Answer: (a) \((-3, 0)\)
Why: Touching at one point means one repeated zero: x² + bx + 9 = (x + 3)² with b = 6.
One point of contact means the polynomial is a perfect square: \(x^2 + bx + 9 = (x + 3)^2\) or \((x - 3)^2\). With \(b \gt 0\), it is \((x + 3)^2\) (\(b = 6\)), whose only zero is \(-3\). The graph touches the \(x\)-axis at \((-3, 0)\). (\((0, 9)\) is where it meets the \(y\)-axis.)
Q12
·1 mark·Multiple choiceRelationship between zeroes and coefficients
A quadratic polynomial whose zeroes have sum \(-4\) and product \(-21\) is
(a)\(x^2 - 4x - 21\)
(b)\(x^2 + 4x + 21\)
(c)\(x^2 - 21x - 4\)
(d)\(x^2 + 4x - 21\)
Show answer
Answer: (d) \(x^2 + 4x - 21\)
Why: Use x² − (sum)x + (product).
\(x^2 - (-4)x + (-21) = x^2 + 4x - 21\). Check: \((x + 7)(x - 3)\) has zeroes \(-7, 3\) with sum \(-4\), product \(-21\).
Q13
·1 mark·Multiple choiceRelationship between zeroes and coefficients
If \(\alpha\) and \(\beta\) are the zeroes of \(2x^2 - 7x + 3\), then \((\alpha - \beta)^2\) equals
Section E of the board paper has three case-based questions of 4 marks: a real-life passage, then parts of 1, 1 and 2 marks, with a choice (OR) on the 2-mark part.
Case study 1: Bakery profit (4 marks)
The owner of a home bakery models her weekly profit (in hundreds of rupees) from selling \(x\) dozen cupcakes by the quadratic polynomial \(P(x) = -x^2 + 14x - 40\). The graph of \(y = P(x)\) is a parabola opening downwards; she makes a profit only where the graph lies above the \(x\)-axis.
(i) Find the zeroes of \(P(x)\). [1 mark]
Show answer
Answer: \(4\) and \(10\)
\(-x^2 + 14x - 40 = -(x - 4)(x - 10)\), so the zeroes are \(4\) and \(10\). A1
(ii) Verify that the sum of the zeroes equals \(-\dfrac{b}{a}\) for \(P(x)\). [1 mark]
Show answer
Answer: \(4 + 10 = 14 = -\dfrac{14}{-1}\)
Sum \(= 4 + 10 = 14\) and \(-\dfrac{b}{a} = -\dfrac{14}{-1} = 14\). A1
(iii) Find the profit when she sells \(7\) dozen cupcakes, and state for which whole numbers of dozens between the zeroes she makes a profit. [2 marks]
Show answer
Answer: ₹900; \(x = 5, 6, 7, 8, 9\)
\(P(7) = -49 + 98 - 40 = 9\), i.e. ₹\(900\) A1. The graph is above the \(x\)-axis between the zeroes, so \(x = 5, 6, 7, 8, 9\). A1
OR Find a quadratic polynomial whose zeroes are each \(2\) more than the zeroes of \(P(x)\). [2 marks]
Show answer
Answer: \(x^2 - 18x + 72\)
New zeroes \(6\) and \(12\) M1: sum \(18\), product \(72\), so \(x^2 - 18x + 72\). A1
Case study 2: Kitchen garden (4 marks)
Meera plans a rectangular kitchen garden on her terrace. Its length is \((x + 5)\) m and its width is \((x - 2)\) m, so its area is \(A(x) = (x + 5)(x - 2) = x^2 + 3x - 10\) square metres.
(i) Without finding the zeroes, write the sum and the product of the zeroes of \(A(x)\). [1 mark]
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Original questions written by CBSE Math Revision for the CBSE 2026-27 syllabus; not taken from NCERT, NCERT Exemplar or CBSE papers. Every answer was re-checked by computer algebra and by an independent reviewer. CBSE Math Revision is independent and not affiliated with CBSE or NCERT. Spotted a slip? Tell us and it goes in the corrections log.