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Class 11 ch 1 · Class 11 ch 2 · Class 12 ch 1

Sets, relations and functions: JEE Main and CUET-style questions

Original JEE Main and CUET-style questions on sets, relations and functions, with a worked solution and the usual trap for each. Tap an option, or type a numerical answer, to check it.

  • 6 questions
  • 3 free
  • 4 multiple choice, 2 numerical value
  • No calculator

Learn the chapters first: Class 11, Sets · Class 11, Relations and Functions · Class 12, Relations and Functions.

Questions

Q1

·JEE Main style·Multiple choiceRelations

Let \(A = \{1, 2, 3, 4\}\). How many relations on \(A\) are both reflexive and symmetric?

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Answer: (a) \(64\)

Reflexive: all four pairs \((a, a)\) must be in the relation, so there is no choice there.

Symmetric: the other pairs come in unordered couples \(\{(a, b), (b, a)\}\) with \(a \ne b\). There are \(\binom{4}{2} = 6\) couples, and each couple is either in (both pairs) or out.

Number of relations \(= 2^6 = 64\).

Trap: Counting the 12 off-diagonal pairs one by one (giving \(2^{12}\)) forgets that symmetry ties each pair to its mirror image.

Q2

·CUET style·Multiple choiceInverse of a function

\(f : \mathbb{R} \setminus \{1\} \to \mathbb{R} \setminus \{2\}\) is given by \(f(x) = \dfrac{2x + 3}{x - 1}\). Then \(f^{-1}(x)\) is

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Answer: (b) \(\dfrac{x + 3}{x - 2}\)

Put \(y = \dfrac{2x + 3}{x - 1}\). Then \(y(x - 1) = 2x + 3\), so \(xy - 2x = y + 3\) and \(x = \dfrac{y + 3}{y - 2}\).

Swap the letters: \(f^{-1}(x) = \dfrac{x + 3}{x - 2}\). Check: \(f(0) = -3\) and \(f^{-1}(-3) = 0\).

Trap: The reciprocal \(\dfrac{x-1}{2x+3}\) is \(1/f(x)\), not the inverse function.

Q3

·JEE Main style·Numerical valueOnto functions

Find the number of onto (surjective) functions from \(\{1, 2, 3, 4, 5\}\) to \(\{a, b, c\}\).

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Answer: 150

All functions: \(3^5 = 243\). Remove those that miss at least one value (inclusion–exclusion):

miss a named value: \(3 \times 2^5 = 96\); miss two named values: \(3 \times 1^5 = 3\) (added back).

Onto functions \(= 243 - 96 + 3 = 150\).

Trap: Subtracting \(3 \times 2^5\) and stopping gives 147: the three constant functions were removed twice.

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All questions are original, written by CBSE Math Revision in the style of each exam; none are taken from NTA, IIT, CBSE or NCERT papers. Every answer was checked twice: by a computer re-solve and by hand. No calculator needed. Spotted a mistake? Tell us.