Children’s Day maths puzzle challenge for CBSE Class 9 and 10
A ready-to-run puzzle challenge for Children’s Day on 14 November: a 5-minute warm-up, four 8–9 minute rounds (number, algebra, geometry and chance) for teams, a bonus round and full worked answers. No calculator.
- Level
- CBSE Class 9 and 10
- Time
- 40 minutes, plus a 10-minute extension
- Topics
- Real numbers: HCF, LCM and remainders; Pair of linear equations; Quadratic equations; Triangles, angles and quadrilaterals; Probability
- Equipment
- No calculator. Every answer works out exactly.
Suggested timings
| Part | Time | What |
|---|---|---|
| Starter | 5 min | Quick questions on the board |
| Main: task A | 9 min | Number round |
| Main: task B | 9 min | Algebra round |
| Main: task C | 9 min | Geometry round |
| Main: task D | 8 min | Chance round |
| Extension | 10 min | Fast finishers or homework |
Starter (5 minutes)
Warm-up: answer on mini whiteboards.
- Today is 14/11. Work out 14 × 11 in your head.
- A number is doubled and then 7 is added. The result is 35. What was the number?
- What is the sum of the interior angles of a hexagon?
- How many prime numbers are there between 1 and 30?
Main activity (35 minutes)
Task A: Number round (9 min)
Teams work together; one answer per team.
- Find the smallest positive whole number that leaves remainder 1 when divided by 2, 3, 4, 5 or 6, and is exactly divisible by 7.
- The HCF of two numbers is 11 and their LCM is 154. One of the numbers is 22. Find the other.
- What is the last digit of 714?
Task B: Algebra round (9 min)
Set up an equation for each puzzle.
- A father is 4 times as old as his daughter. In 14 years he will be twice as old as her. How old are they now?
- The sum of a positive number and its reciprocal is 10/3. Find the number (two answers).
- 3 pens and 2 notebooks cost ₹110. 2 pens and 3 notebooks cost ₹115. Find the cost of one pen and one notebook.
Task C: Geometry round (9 min)
Draw a sketch first.
- A right-angled triangle has shorter sides 9 cm and 12 cm. Find its hypotenuse and its area.
- The angles of a quadrilateral are in the ratio 3 : 4 : 5 : 6. Find the largest angle.
- What is the angle between the hour and minute hands of a clock at 3:30?
Task D: Chance round (8 min)
Write each answer as a fraction in its lowest terms.
- Two dice are thrown. Find the probability that the total is 7.
- A card is picked at random from cards numbered 1 to 50. Find the probability that the number is a multiple of 4 or of 6.
- A coin is tossed three times. Find the probability of at least two heads.
Extension (10 minutes)
Bonus round for the fastest teams.
- How many squares of all sizes are there on an 8 by 8 chessboard?
- The sum of three consecutive odd numbers is 147. Find the numbers.
For teachers
Teacher notes and full worked answers
- Run it as a team quiz: teams of three or four, one answer sheet per team, one mark per correct answer, and 1 extra mark for clear working in the algebra round.
- The rounds are independent, so you can use one round as a starter on another day.
- In the number round, the clock and last-digit questions reward spotting a repeating pattern: ask teams to explain how they found it.
Starter
- 154
- 14 × 11 = 140 + 14 = 154
- 14
- 2x + 7 = 35, so 2x = 28 and x = 14.
- 720°
- (6 − 2) × 180° = 720°
- 10
- 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
Task A: Number round
- 301
- Remainder 1 when divided by 2, 3, 4, 5 and 6 means one more than a multiple of LCM(2, 3, 4, 5, 6) = 60.
- Try 61, 121, 181, 241, 301: the first multiple of 7 is 301 = 7 × 43.
- 77
- HCF × LCM = product of the numbers: 11 × 154 = 1694.
- 1694 ÷ 22 = 77
- 9
- The last digits of 7, 72, 73, 74 are 7, 9, 3, 1, and then the pattern repeats every 4.
- 14 = 4 × 3 + 2, so the last digit is the same as for 72: 9.
Task B: Algebra round
- Daughter 7, father 28
- Let the daughter be x: 4x + 14 = 2(x + 14).
- 4x + 14 = 2x + 28, so 2x = 14 and x = 7. The father is 28.
- 3 or 1/3
- x + 1/x = 10/3 gives 3x2 − 10x + 3 = 0.
- (3x − 1)(x − 3) = 0, so x = 3 or 1/3.
- Pen ₹20, notebook ₹25
- Add the equations: 5p + 5n = 225, so p + n = 45.
- Subtract them: p − n = −5.
- So 2p = 40: p = 20 and n = 25.
Task C: Geometry round
- 15 cm; 54 cm2
- √(81 + 144) = √225 = 15
- Area = ½ × 9 × 12 = 54
- 120°
- 3 + 4 + 5 + 6 = 18 parts = 360°, so 1 part = 20°.
- Largest = 6 × 20° = 120°
- 75°
- The minute hand points at 6: 180° from 12.
- The hour hand is halfway from 3 to 4: 90° + 15° = 105° from 12.
- 180° − 105° = 75°
Task D: Chance round
- 1/6
- (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1): 6 of the 36 outcomes.
- 6/36 = 1/6
- 8/25
- Multiples of 4: 12. Multiples of 6: 8. Multiples of both (of 12): 4.
- 12 + 8 − 4 = 16, so 16/50 = 8/25.
- 1/2
- HHH, HHT, HTH, THH: 4 of the 8 outcomes.
- 4/8 = 1/2
Extension
- 204
- There are 82 squares of size 1 by 1, 72 of size 2 by 2, and so on down to 12 of size 8 by 8.
- 64 + 49 + 36 + 25 + 16 + 9 + 4 + 1 = 204
- 47, 49, 51
- (x − 2) + x + (x + 2) = 3x = 147, so x = 49.
The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.
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