The next term of the sequence \(3, 7, 11, 15, \ldots\) is
- (a)\(19\)
- (b)\(18\)
- (c)\(20\)
- (d)\(22\)
Revision notes, 17 board-style questions with the step marks shown, and a four-step route from the basics to 95+, each step ending in a short checkpoint.
Algebra unit: 20 of 80 theory marks (Introduction to Polynomials, Sequences and Progressions, Exploring Algebraic Identities, Linear Equations in Two Variables).
In the NCERT book Ganita Manjari: Part I, Chapter 8, Predicting What Comes Next: Exploring Sequences and Progressions.
A sequence is a list of numbers in a definite order: \(a_1, a_2, a_3, \ldots\). It can be given by
\(1, 1, 2, 3, 5, 8, 13, \ldots\): each term after the second is the sum of the two before, \(F_{n+1} = F_n + F_{n-1}\). Virahanka found these numbers by counting the rhythms of poetic metres (in 1 and 2 beats) centuries before Fibonacci.
An AP adds the same number \(d\) (the common difference) each time: \(a, a + d, a + 2d, \ldots\) with
\[a_n = a + (n - 1)d\]
Recursively, \(a_{n+1} = a_n + d\). Its graph (term against \(n\)) is a set of points on a straight line: linear growth.
\[1 + 2 + 3 + \cdots + n = \frac{n(n + 1)}{2}\]
Write the sum forwards and backwards: each of the \(n\) columns adds to \(n + 1\), so twice the sum is \(n(n + 1)\). Also \(1 + 3 + 5 + \cdots + (2n - 1) = n^2\).
A GP multiplies by the same number \(r\) (the common ratio) each time: \(a, ar, ar^2, \ldots\) with \(a_n = ar^{n-1}\). Recursively, \(a_{n+1} = r\,a_n\). Doubling, halving and repeated percentage change are GPs.
Which term of the AP \(4, 11, 18, \ldots\) is \(144\)?
\(4 + 7(n - 1) = 144 \Rightarrow n - 1 = 20 \Rightarrow n = 21\).
Find the \(6\)th term of the GP \(2, 6, 18, \ldots\).
\(r = 3\): \(a_6 = 2 \times 3^5 = 486\).
Find \(1 + 2 + \cdots + 40\).
\(\dfrac{40 \times 41}{2} = 820\).
Topics in this chapter: Arithmetic progressions · Geometric progressions · Sequences and their rules · Patterns from repeated processes · Virahanka-Fibonacci sequence · Sum of the first n natural numbers.
Work through the steps in order. Take each checkpoint closed book, about 1.5 minutes per mark; pass at 80% to move on. Two misses in a row means going back one step.
You can continue a pattern, spot an AP or a GP and find a term from an explicit or recursive rule.
You can find which term has a given value, find a and d from two terms and add 1 + 2 + … + n.
You can model salaries, seating and growth with APs and GPs and answer every part of a case study.
You can reason about fractals, the Tower of Hanoi and sums with exclusions such as 'not multiples of 5'.
Original questions in the board's styles. Multiple-choice answers are checked as you go; for written answers, compare your working with the step mark scheme and record your marks. 3 of the 17 are competency-based (case studies and questions set in a real-life situation): the "Competency-based" button shows just those.
The next term of the sequence \(3, 7, 11, 15, \ldots\) is
The common ratio of the GP \(5, 15, 45, \ldots\) is
The \(10\)th term of the AP \(2, 5, 8, \ldots\) is
Stretch yourself: original algebra problems at Intermediate level (ages 13 to 16), with hints and full solutions: Problem I104 · Problem I111 · Problem I118 · Problem I169. All 29 →
Want it against the clock? Take a timed 30-mark chapter test on Sequences and Progressions, new questions each time, or climb the Difficulty ladder, levels 1 to 10, three questions a level (CBSE Essentials or the free trial).