NCERT Solutions for Class 12 Maths Chapter 13: Probability
Conditional probability, the multiplication rule, independent events, the theorem of total probability and Bayes' theorem. Our own step-by-step solutions to Exercises 13.1 to 13.3 and the Miscellaneous Exercise, one page per exercise, set out for step marks.
4 exercises, 62 questions
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Chapter 13 exercises
Each exercise has its own page with every question solved step by step. Pick the one you are on.
What it tests. \(P(E|F) = \dfrac{P(E \cap F)}{P(F)}\) (\(P(F) \ne 0\)): restrict the sample space to F. With equally likely outcomes, \(P(E|F) = \dfrac{n(E \cap F)}{n(F)}\). \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).
What it tests. \(P(E \cap F) = P(E)P(F|E)\); for draws without replacement multiply the changing fractions. E and F are independent when \(P(E \cap F) = P(E)P(F)\) (then their complements are independent too), so 'at least one' \(= 1 - P(\text{none})\).
What it tests. If \(E_1, \ldots, E_n\) partition the sample space: \(P(A) = \sum P(E_i)P(A|E_i)\) (total probability) and \(P(E_i|A) = \dfrac{P(E_i)P(A|E_i)}{\sum_j P(E_j)P(A|E_j)}\) (Bayes). Name the events, write the priors \(P(E_i)\) and the likelihoods \(P(A|E_i)\), then substitute; a tree diagram keeps the products straight.
Done the NCERT exercises? The board paper asks more
Probability has 39 original board-style questions (MCQ, assertion–reason, short and long answers, case studies) with step mark schemes, revision notes and a four-step Route to 95. Three sample questions are open to everyone; a free account opens the rest.
Textbook: NCERT Mathematics Class 12, Parts I and II (rationalised edition, 2023-24 reprint onward), free from ncert.nic.in. Question statements are shortened to the minimum needed; the solutions and tips are our own. CBSE Math Revision is independent and not affiliated with NCERT or CBSE. Spotted a slip? Tell us and it goes in the corrections log.