The value of \(\dfrac{8!}{6!}\) is
- (a)\(2\)
- (b)\(48\)
- (c)\(56\)
- (d)\(\dfrac43\)
Revision notes, 17 board-style questions with the step marks shown, and a four-step route from the basics to 95+, each step ending in a short checkpoint.
Algebra unit: 25 of 80 theory marks (Complex Numbers and Quadratic Equations, Linear Inequalities, Permutations and Combinations, Binomial Theorem, Sequences and Series).
If one event can happen in \(m\) ways and, after it, another in \(n\) ways, the two together can happen in \(mn\) ways (multiplication principle). Use "and" \(\to\) multiply; "or" (cases that cannot both happen) \(\to\) add.
\(n! = 1 \times 2 \times \cdots \times n\), \(0! = 1\), \(n! = n \times (n - 1)!\). Simplify quotients before multiplying: \(\dfrac{8!}{6!} = 8 \times 7 = 56\).
Selections of \(r\) from \(n\) different objects: \({}^nC_r = \dfrac{n!}{r!(n - r)!} = \dfrac{{}^nP_r}{r!}\). Properties: \({}^nC_r = {}^nC_{n-r}\); \({}^nC_r + {}^nC_{r-1} = {}^{n+1}C_r\); if \({}^nC_a = {}^nC_b\) then \(a = b\) or \(a + b = n\).
Arranging, ordering, forming numbers or words \(\to\) permutations. Choosing a team, committee or group \(\to\) combinations. Mixed problems: first select (combinations), then arrange (permutations). Deal with restrictions (a digit that cannot be first, people who must be included) first.
How many 3-digit numbers with distinct digits can be formed from \(1, 2, 3, 4, 5\)?
\({}^5P_3 = 5 \times 4 \times 3 = 60\).
In how many ways can a committee of \(3\) be chosen from \(9\) people?
\({}^9C_3 = \dfrac{9 \times 8 \times 7}{6} = 84\).
How many arrangements are there of the letters of LEVEL?
\(\dfrac{5!}{2!\,2!} = 30\) (two L's, two E's).
Topics in this chapter: Factorial · Permutations · Combinations · Fundamental principle of counting.
Work through the steps in order. Take each checkpoint closed book, about 1.5 minutes per mark; pass at 80% to move on. Two misses in a row means going back one step.
You can use the multiplication principle, simplify factorials and apply nPr and nCr directly.
You can solve for n in nPr / nCr equations, count words with restrictions and form committees.
You can combine selection and arrangement in multi-part problems about words, numbers and teams.
You can handle divisibility and digit restrictions and 'must include / must exclude' selections.
Original questions in the board's styles. Multiple-choice answers are checked as you go; for written answers, compare your working with the step mark scheme and record your marks. 2 of the 17 are competency-based (case studies and questions set in a real-life situation): the "Competency-based" button shows just those.
The value of \(\dfrac{8!}{6!}\) is
The number of 3-digit numbers with distinct digits that can be formed from \(1, 2, 3, 4, 5\) is
If \({}^nC_2 = 45\), then \(n\) is
Stretch yourself: 7 competition-style combinatorics problems (Senior, ages 16 to 18), original, with hints and full solutions. More extension & competition maths →
Want it against the clock? Take a timed 30-mark chapter test on Permutations and Combinations, new questions each time (CBSE Essentials or the free trial).