Spring egg geometry for CBSE Class 10
A ready-to-teach lesson for spring: model eggs with combinations of solids, melt and recast chocolate, and pack an egg in a box. A 5-minute starter, a 35-minute main activity, an extension and full worked answers. No calculator; use π = 22/7.
- Level
- CBSE Class 10 (Class 9 can try most of it)
- Time
- 40 minutes, plus a 10-minute extension
- Topics
- Surface areas and volumes: combinations of solids; Converting one solid to another; Volume and surface area of spheres, hemispheres, cones and cubes
- Equipment
- No calculator. Use π = 22/7 throughout.
Suggested timings
| Part | Time | What |
|---|---|---|
| Starter | 5 min | Quick questions on the board |
| Main: task A | 12 min | A hemisphere-and-cone egg |
| Main: task B | 12 min | Melt and recast |
| Main: task C | 11 min | An egg in a box |
| Extension | 10 min | Fast finishers or homework |
Starter (5 minutes)
Quick-fire mental maths. Use π = 22/7.
- Find the curved surface area of a hemisphere of radius 7 cm. (Use π = 22/7.)
- Find the volume of a cone of radius 7 cm and height 6 cm. (Use π = 22/7.)
- Find the slant height of a cone with radius 6 cm and height 8 cm.
- Find the surface area of a sphere of radius 7 cm. (Use π = 22/7.)
Main activity (35 minutes)
Task A: A hemisphere-and-cone egg (12 min)
A wooden egg is a hemisphere of radius 7 cm joined to a cone of radius 7 cm and height 24 cm. Use π = 22/7.
- Find the volume of the egg.
- Find the total surface area of the egg.
- The egg is painted at ₹0.50 per cm2. Find the cost.
Task B: Melt and recast (12 min)
Use π = 22/7.
- A solid chocolate sphere of radius 7 cm is melted and made into small spheres of radius 1.75 cm. How many small spheres are made?
- A cylinder of radius 7 cm and height 20 cm is full of melted chocolate. It is poured into hemispherical moulds of radius 3.5 cm. How many moulds can be filled completely?
- Find the surface area of one small sphere of radius 3.5 cm, to wrap it in foil.
Task C: An egg in a box (11 min)
A spherical chocolate egg of radius 3.5 cm fits exactly inside a cube-shaped box of side 7 cm. Use π = 22/7.
- Find the volume of empty space in the box.
- What fraction of the box does the egg fill?
- The box has no lid. Find the area of card needed to make it.
Extension (10 minutes)
For fast finishers, or as homework.
- An egg is a hemisphere of radius 7 cm on a cone of radius 7 cm. What height must the cone have for the cone and the hemisphere to have equal volumes?
- How many spheres of radius 1 cm can be made by melting a sphere of radius 5 cm? What is the ratio of the total surface area of the small spheres to that of the big sphere?
For teachers
Teacher notes and full worked answers
- These are typical ‘combination of solids’ and ‘conversion of solids’ questions in a spring setting.
- In task A (b), remind students that the flat circle where the two solids join is inside the egg, so it is not painted.
- In task B (b), insist on complete moulds: 34, not 34.28.
Starter
- 308 cm2
- 2 × 22/7 × 7 × 7 = 308
- 308 cm3
- 1/3 × 22/7 × 49 × 6 = 308
- 10 cm
- √(36 + 64) = 10
- 616 cm2
- 4 × 22/7 × 49 = 616
Task A: A hemisphere-and-cone egg
- 5852/3 = 1950 2/3 cm3
- Hemisphere: 2/3 × 22/7 × 343 = 2156/3.
- Cone: 1/3 × 22/7 × 49 × 24 = 1232.
- 2156/3 + 1232 = 5852/3
- 858 cm2
- Slant height = √(49 + 576) = 25.
- Hemisphere: 2 × 22/7 × 49 = 308. Cone: 22/7 × 7 × 25 = 550.
- 308 + 550 = 858
- ₹429
- 858 × 0.5 = 429
Task B: Melt and recast
- 64
- (7/1.75)3 = 43 = 64 (the 4/3 × π cancels).
- 34
- Cylinder: 22/7 × 49 × 20 = 3080 cm3.
- Mould: 2/3 × 22/7 × 42.875 = 539/6 cm3.
- 3080 ÷ 539/6 = 18 480/539 = 34.28…, so 34 moulds.
- 154 cm2
- 4 × 22/7 × 3.5 × 3.5 = 154
Task C: An egg in a box
- 490/3 = 163 1/3 cm3
- Cube: 343. Sphere: 4/3 × 22/7 × 42.875 = 539/3.
- 343 − 539/3 = 490/3
- 11/21
- (539/3) ÷ 343 = 539/1029 = 11/21
- 245 cm2
- 5 faces × 49 = 245
Extension
- 14 cm
- 1/3 × π × 49 × h = 2/3 × π × 343 gives 49h = 686, so h = 14.
- 125; 5 : 1
- (5/1)3 = 125
- 125 × 4π × 1 : 4π × 25 = 500π : 100π = 5 : 1
The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.
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